How to find the equation of a plane perpendicular to another plane?

Find the equation of a plane perpendicular to x + y + z = d containing the points (x1, y1, z1) and (x2, y2, z2)|||I will assume the points given , P1 %26amp; P2, are in the new plane. The normal to the new plane is vector P1P2 x %26lt;1,1,1%26gt;, so the required equation is


{[y1-y2] - [z1-z2]} (x-x1) + { [z1-z2] - [x1-x2]} ( y-y1) + {[ x1-x2] - [y1-y2]} ( z-z1) = 0