A criminal escapes a plane in a jet plane. 54 minutes later the police takes off in pursuit?

A criminal escapes a plane in a jet plane. 54 minutes later the police takes off in pursuit. The police can fly 12% faster than the criminal's plane. Assuming both planes fly the same route, how many minutes will take for the police plane to overtake the criminal's plane?|||Call the speed of the criminal's plane x (miles per minute)

That means the police plane travels at 112% * x (miles per minute)

Distance = rate x time

Let t represent your time in the problem.

At the the time t that the police catch up, they have been flying for t minutes, and the criminal for t + 54 minutes

x(t+54) = 112%xt

Distribute the x to the (t+54) in parentheses.

xt + 54x = 1.12xt

Subtract xt on both sides to balance out the equation.

54x = 0.12xt

Eliminate your Xs to simplify the problem.

54 = 0.12t

Divide by 0.12 on each side.

t = 450 minutes

Thus, if both planes fly the same route, it will take 450 minutes or seven and a half hours for the police place the overtake the criminal's plane.

Hope I helped!

Maxwell|||Call the speed of the criminal's plane x (miles/minute)





That means the police plane travels at 112% * x (miles/minute)


Distance = speed * time


At the the time t that the polic catch up, they have been flying for t minutes, and the criminal for t + 54 minutes





x(t+54) = 112%xt


xt + 54x = 1.12xt


54x = 0.12xt


54 = 0.12t


t = 54/0.12 = 450