A plane is traveling at 500 meters of height at a velocity of 150m/s. When the plane drops a box from this height and speed, what is the distance the box travels? Neglect air resistance.
Honestly This was on a test today and I don't remember if its 1,500 or 15 meters.|||We will solve the following problem by resolve the projectile motion of the box into its vertical and horizontal components.
Vertical component of the box's projectile motion:
uyt+0.5at^2 = Sy
150sin0*t+0.5*9.8*t^2 = 500
4.9t^2 = 500
t = (+)√(500/4.9)
and ignore the negative sign of the solution.
Horizontal component of the box's projectile motion:
Range = U
= (Uh)*t
= {150*[√(500/4.9)]}m
= 1515.23m
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment